In three-way ties for two wild-card spots, baseball's rules state:
“After Clubs have been assigned their A, B and C designations, Club A would host Club B on Monday, Sept. 30 (tentatively). The winner of the game would be declared one Wild Card winner. Club C would then host the loser of the game between Club A and Club B on Tuesday, Oct. 1 (tentatively) to determine the second Wild Card Club.”
Translation: The Indians would get first dibs on choosing their “designation,” and the Tribe would almost assuredly choose “A” — meaning the Indians would host Club B (likely the Rays, since the Rays would have the second choice in the tiebreaker procedure and, by choosing “B,” Tampa would have two chances to earn one of the wild-card berths) on Monday, Sept. 30.